The value of ∫dxx+x3 is
3x+3(x3)−6x6+6log(x6+1)+C
2x+6(x6)−6log(x6+1)+C
2x−3(x3)+6(x6)−6log(x6+1)+C
None of the above
Let I=∫dxx+x3
Now let x=t6⇒dx=6t5dt
⇒ I=∫6t0t3+t2dt=6∫t3t+1dt=6∫t2−t+1−1t+1dt=2t3−3t2+6t−6log(t+1)+C=2x−3(x3)+6(x6)−6log(x6+1)+C