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The value of is
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a
1
b
36C17
c
219
d
36C18
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Correct option is A
We have(1+k)1+k21+k3â¦1+kn=(1+k)(2+k)(3+k)â¦(n+k)(2)(3)â¦(n)=(n+k)!k!n!=n+kCkThus, both the numerator and the denominator of E equals 36C17=36C19 â â´ E=1.Similar Questions
is equal to
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