The value of 78.6elimx→01+x1xe1x is

Let P=limx→0 (1+x)1/xe1/x=elimx→01+x1xe-11x=e1elimx→0 (1+x)1/x−ex                        =e1e(−e/2)=e−1/2=1e     since limx→0 (1+x)1/x−ex=limx→0e1-x2+1124x2..-ex =-e2        ∴78.6elimx→0 (1+x)1/xe1/x=78.6e⋅1e=78.6