the value of ∫etanθ(secθ−sinθ)dθis
etanθsecθ+c
etanθsinθ+c
etanθ(secθ+sinθ)+c
etanθcosθ+c
Let I=∫etanθ(secθ−sinθ)dθ
Put tanθ=t⇒sec2θdθ=dt⇒dθ=dt1+t2
⇒I=∫et(1+t2−t1+t2)dt1+t2
=∫et(11+t2−1(1+t2)3/2)dt
=∫et(f+f')dt=et.f(t)
=et1+t2+c =etanθcosθ+c