First slide
Evaluation of definite integrals
Question

The value of 1/etanxt1+t2dt+1/ecotxdtt1+t2 is

Moderate
Solution

1t1+t2=1tt1+t2So the required integral is  equal to

1etanxtdx1+t2+1ecotxdtt1ecotxtdt1+t2=12log1+t21etanx+logt1ecotx12log1+t21ecotx=log|secx|+log|cotx|+1log|cosecx|=1

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