First slide
Algebra of complex numbers
Question

 The value of the expression 1+1ω1+1ω2+2+1ω2+1ω2+3+1ω3+1ω2+.+n+1ωn+1ω2 where ω is an imaginary cube root of unity, is 

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Solution

We have k=1nk+1ωk+1ω2= k=1nk+ω2k+ω  ω3=1                                               = k=1nk2+kω+ω2+ω3                                               = k=1nk2-k+1     1+ω+ω2=0                                               =nn+12n+16-nn+12+n                                               =nn2+23

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