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Q.

The value of the expression 2sin2⁡91∘−12sin2⁡92∘−1…2sin2⁡180∘−1 is equal to

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a

0

b

1

c

290

d

290-90

answer is A.

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Detailed Solution

2sin2⁡91∘−12sin2⁡92∘−1…2sin2⁡180∘−1In this product there exists a factor 2sin2⁡135∘−1 which is equal to zeroThus, the product of all terms is zero.
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