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Q.

The value of f(0) so that the function f(x)=log1+xa−log1−xbx,(x≠0) is continuous at x = 0 is

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a

a+bab

b

a−bab

c

aba+b

d

aba-b

answer is A.

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Detailed Solution

limx→0f(x)=limx→0log1+xa−log1−xbx 00 form by L'hospital rule =ltx→0 11+xa 1a+11+xb 1b1 =1a+1b=a+bab

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