First slide
Evaluation of definite integrals
Question

The value I=11cos1x+x73x5+7x3xcos2xdx is 

Moderate
Solution

Let f(x)=x73x5+7x3xcos2x then f(x)=f(x) so 11f(x)dx=0                  (Property 12)

Let g(x)=cos1 x then I1=11cos1 xdx

=11cos1 (x)dx                       (Property 8)

=11πcos1 xdx=2πI1

Thus I=I1=π. 

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