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The value I=11cos1x+x73x5+7x3xcos2xdx is 

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a
π/2
b
0
c
d
π

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detailed solution

Correct option is D

Let f(x)=x7−3x5+7x3−xcos2x then f(−x)=−f(x) so ∫−11 f(x)dx=0                  (Property 12)Let g(x)=cos−1⁡ x then I1=∫−11 cos−1⁡ xdx=∫−11 cos−1⁡ (−x)dx                       (Property 8)=∫−11 π−cos−1⁡ xdx=2π−I1Thus I=I1=π.


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