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a
π/2
b
0
c
2π
d
π
answer is D.
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Detailed Solution
Let f(x)=x7−3x5+7x3−xcos2x then f(−x)=−f(x) so ∫−11 f(x)dx=0 (Property 12)Let g(x)=cos−1 x then I1=∫−11 cos−1 xdx=∫−11 cos−1 (−x)dx (Property 8)=∫−11 π−cos−1 xdx=2π−I1Thus I=I1=π.