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a
−215
b
−215i
c
215i
d
65
answer is B.
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Detailed Solution
we know that -1+i3=2ω where ω is cube root of unityHence, −1+i330=230ω30=230 since ω3=1And (1-i)2=1+i2-2i=-2i Hence, (1-i)30=(-2i)15=-215(-i)=215i Therefore, -1+i31-i30=230215i=215(-i) since i15=i43i3=-i