The value of the integral ∫0100π 1−cos 2xdx is
1002
2002
0
100π
We have 1−cos 2x=2|sin x|. Since the period of |sin x| is π,
so ∫0100π 1−cos 2xdx=2∫0100π |sin x|dx=1002∫0π sin x dx=2002.