Questions
The value of the integral
is
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a
π/2
b
π/4
c
-π/2
d
none of these
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Correct option is C
ddxtan−11x=11+1x2−1x2=−11+x2⇒ I=∫−11 ddxtan−11xdx=∫−11 −dx1+x2=−tan−1x−11=−π4+−π4=−π2Note that I=tan−1(1/x)−11=π4−−π4=π2 is incorrect,since the function tan−1(1/x) is not an antiderivative of (d/dx)tan−1(1/x) on the interval[−1,1]Similar Questions
The value of is
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