First slide
Evaluation of definite integrals
Question

The value of integral k=1n01f(k1+x)dx is

Moderate
Solution

 Let     I=01f(k1+x)dx    I=k1kf(t)dt, where t=k1+x    I=k1kf(x)dx    k=1nk1kf(x)dx=    01f(x)dx+12f(x)dx++n1nf(x)dx=0nf(x)dx

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