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The value of the integral 1/n(an1)/nxax+xdx is 

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a
a2
b
na+22n
c
na-22n
d
None of these

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detailed solution

Correct option is C

I=∫1/n(an−1)/n xa−x+xdx=∫1/na−(1/n) xa−x+xdx----i=∫1/na−(1/n) 1n+a−1n−xdxa−1n+a−1n−x+1n+a−1n−x⇒I=∫1na−1n a−xx+a−xdx----iiOn adding Eqs. (1) and (ii), we get2I=∫1/na−(1/n) 1dx=[x]1na−1n⇒ 2I=a−1n−1n=na−2n⇒I=na−22n


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