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The value of the integral 0nπ+t(|cos x| + |sin x|) dx is 

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a
n
b
2n+sin t+cos t
c
cos t
d
sin t–cos t+4n+1

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detailed solution

Correct option is D

Since the period of |sin⁡ x|+|cos⁡ x is π/2∫0nπ+t (|sin⁡ x|+|cos⁡ x|)dx=2n∫0π/2 (|sin⁡ x|+|cos⁡ x|)dx+∫0t (|sin⁡ x|+|cos⁡ x|)dx=2n∫0π/2 (sin⁡ x+cos⁡ x)dx+∫0t (sin⁡ x+cos⁡ x)dx=(2n)(2)+sin⁡ t−cos⁡ t+1=(4n+1)+sin⁡ t−cos⁡ t.


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