Questions
The value of the integral is
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a
log 2
b
log 3
c
(1/4) log 3
d
(1/8) log 3
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Correct option is C
The integral can be written −∫0π/4 sin x+cos x(sin x−cos x)2−4dx.Now put t=sin x−cosx. Then dt=(cos x+sinx)dx and the integral becomes−∫−10 dtt2−4=−14log t−2t+2−10=−14(log 1−log3)=14log 3.Similar Questions
is equal to
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