The value of the integral ∫0π/4 sin x+cos x3+sin 2xdx is
log 2
log 3
(1/4) log 3
(1/8) log 3
The integral can be written
−∫0π/4 sin x+cos x(sin x−cos x)2−4dx.
Now put t=sin x−cosx. Then dt=(cos x+sinx)dx and the integral becomes
−∫−10 dtt2−4=−14log t−2t+2−10=−14(log 1−log3)=14log 3.