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The value of the integral 0π/4sinx+cosx3+sin2xdx is

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a
log 2
b
log 3
c
(1/4) log 3
d
(1/8) log 3.

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detailed solution

Correct option is C

Put sin⁡x−cos⁡x=t so thatI=∫−10 dt3+1−t2=12(2)log⁡2+t2−t−10=14log⁡3.


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