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The value of the integral  π/3π/3xsinxcos2xdx is

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a
π3−log⁡tan⁡3π2
b
22π3−log⁡(2+3)
c
3π2−log⁡tan⁡π12
d
none of these

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detailed solution

Correct option is B

The integrand is an even function, so the given integral is equal to2∫0π/3 xsin⁡xcos2⁡xdx=2[xsec⁡x]0π−∫0π/3 sec⁡xdx=2⋅π3⋅2−2[log⁡(sec⁡x+tan⁡x)]05=4π3−2log⁡(2+3)


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