First slide
Methods of integration
Question

 The value of the integral x2+xx8+2x91/10dx is 

Moderate
Solution

I=x2+xx8+2x91/10dx=(x+1)x2+2x1/10dx Put x2+2x=t(x+1)dx=dt2 Now, I=t110dt2=12×1011t1110=511t1110+c I=511x2+2x1110+c

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