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 The value of the integral x2+xx8+2x91/10dx is 

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a
511x2+2x11/10+c
b
56(x+1)11/10+c
c
67(x+1)11/10+c
d
None of these

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detailed solution

Correct option is A

I=∫x2+xx−8+2x−91/10dx=∫(x+1)x2+2x1/10dx Put x2+2x=t⇒(x+1)dx=dt2 Now, I=∫t110⋅dt2=12×1011t1110=511t1110+c∴ I=511x2+2x1110+c


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