The value of the integral ∫x2+xx−8+2x−91/10dx is
511x2+2x11/10+c
56(x+1)11/10+c
67(x+1)11/10+c
None of these
I=∫x2+xx−8+2x−91/10dx=∫(x+1)x2+2x1/10dx Put x2+2x=t⇒(x+1)dx=dt2 Now, I=∫t110⋅dt2=12×1011t1110=511t1110+c∴ I=511x2+2x1110+c