First slide
Binomial theorem for positive integral Index
Question

The value of k=0n 4n+1Ck+4n+1C2nk is 

Moderate
Solution

 k=0n 4n+1Ck+4n+1C2nk=k=02n 4n+1Ck+4n+1C2n=24n+4n+1C2n     

                                                 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App