Download the app

Questions  

The value of k=0n 4n+1Ck+4n+1C2nk is 

a
24n+4n+1C2n
b
24n+1
c
24n
d
24n+1+4n+1Cn

detailed solution

Correct option is A

∑k=0n  4n+1Ck+4n+1C2n−k=∑k=02n  4n+1Ck+4n+1C2n=24n+4n+1C2n

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

If the coefficients of  P th, ( p + 1)th and (p + 2)th terms in the expansion of (1 + x)n are in AP, then


phone icon
whats app icon