First slide
Continuity
Question

The value of k so that the function f(x)={kcosxπ2xxπ23,x=π2  is continuous at x=π2  is

Very Easy
Solution

fπ2=limxπ2kcos2xπ-2x 00 form by L'Hospital rule 3= limxπ2-ksin2x-2=k2k=6

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