The value of k for which (a+2b) where a,b≠0 is a factor of a4+32b4+a3b(k+3) is
3
0
1
2
Let f(a)=a4+32b4+a3b(k+3) f(−2b)=(−2b)4+32b4+(−2b)3b(k+3)=0⇒ 48b4−8b4(k+3)=0⇒ 8b4[6−(k+3)]=0⇒ 8b4(3−k)=0 Since b≠0,3−k=0.