First slide
Theory of equations
Question

 The value of k for which (a+2b) where a,b0 is a factor  of a4+32b4+a3b(k+3) is 

Moderate
Solution

 Let f(a)=a4+32b4+a3b(k+3) f(2b)=(2b)4+32b4+(2b)3b(k+3)=0 48b48b4(k+3)=0 8b4[6(k+3)]=0 8b4(3k)=0 Since b0,3k=0.

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