The value of k for which the function f(x)=sin1xx≠0kx=0 is continuous is
8
1
−1
None of these
Since, f(x)=sin1xx≠0kx=0
If f(x) is continuous at x=0
limx→0f(x)=f(0)=k
⇒limx→0sin1x=k
⇒ k=sin∞ can take any finite value between −1 and 1
∴ f(x) is discontinuous at x=0 .