The value of k  for which the function f(x)=sin1xx≠0kx=0  is continuous is

Since, f(x)=sin1xx≠0kx=0 If f(x)  is continuous at x=0limx→0f(x)=f(0)=k⇒limx→0sin1x=k⇒ k=sin∞  can take any finite value between −1  and 1∴  f(x)  is discontinuous at x=0 .