The value of k for which one of the roots of x2−x+3k=0 is double of one of the roots of x2−x+k=0 is
1
−2
2
None of these
Let α be a root of x2−x+k=0 ,
then 2α is a root of x2−x+3k=0 .
Then the equations are α2−α+k=0 ….. ( 1 )
and 4α2−2α+3k=0 ….. ( 2 )
solve ( 1 ) & ( 2 )
we get,
⇒ α2−3k+2k=α4k−3k=1−2+4
⇒ α2=−k2 and α=k2
Now, α2=(α)2⇒−k2=(k2)2
⇒ k2+2k=0⇒k=−2 (k not equals to 0)