First slide
Theory of equations
Question

The value of k  for which one of the roots of x2x+3k=0  is double of one of the roots of x2x+k=0  is

Moderate
Solution

Let α  be a root of x2x+k=0 ,

then 2α  is a root of x2x+3k=0 .

Then the equations are α2α+k=0  ….. ( 1 )

and 4α22α+3k=0   ….. ( 2 )

solve ( 1 ) & ( 2 )

we get,

  α23k+2k=α4k3k=12+4

  α2=k2  and α=k2

Now, α2=(α)2k2=(k2)2

 k2+2k=0k=2 (k not equals to 0)

 

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