First slide
Introduction to limits
Question

 The value of θ, is limθ0cos21-cos21-cos2.1-cos21-cos2θsinπθ+4-2θ

Moderate
Solution

limθ0cos21-cos21-cos2.1-cos21-cos2θsinπθ+4-2θlimθ0cos21-cos21-cos2.1-cos21-cos2θsinπ(θ+4-2)θ.(θ+4+2)(θ+4+2)limθ01sinπθ+4+2=1sinπ4=2

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