The value of limh→0 ln⁡(1+2h)−2ln⁡(1+h)h2, is

We have, limh→0 log⁡(1+2h)−2log⁡(1+h)h2=limh→0 log⁡1+2h(1+h)2h2=−limh→0 log⁡(1+h)21+2hh2=−limh→0 log⁡1+h21+2hh21+2h(1+2h)=−1=−1.