First slide
Introduction to limits
Question

The value of limh0ln(1+2h)2ln(1+h)h2, is

Moderate
Solution

We have, 

limh0log(1+2h)2log(1+h)h2=limh0log1+2h(1+h)2h2=limh0log(1+h)21+2hh2=limh0log1+h21+2hh21+2h(1+2h)=1=1.

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