The value of limh→0 ln(1+2h)−2ln(1+h)h2, is
1
-1
0
none of these
We have,
limh→0 log(1+2h)−2log(1+h)h2=limh→0 log1+2h(1+h)2h2=−limh→0 log(1+h)21+2hh2=−limh→0 log1+h21+2hh21+2h(1+2h)=−1=−1.