First slide
Introduction to limits
Question

The value of 

limh023sinπ6+hcosπ6+hh(3sinhcosh) is

Moderate
Solution

limh023sinπ6+hcosπ6+hh(3sinhcosh)

=limh0432sinπ6+h12cosπ6+hh(3sinhcosh)=limh04sinπ6+hcosπ6cosπ6+hsinπ6h(3sinhcosh)=limh04sinπ6+hπ6h(3sinhcosh)=4limh0sinhh(3sinhcosh)=4

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