The value of limn→∞ 1⋅2+2⋅3+3⋅4+…+n(n+1)n3 ,is
1
-1
13
none of these
We have,
limn→∞ 1⋅2+2⋅3+3⋅4+…+n(n+1)n3=limn→∞ ∑r=1n r(r+1)n3=limn→∞ ∑r=1n r2+∑r=1n rn3=limn→∞ n(n+1)(2n+1)6+n(n+1)2n3=limn→∞ n(n+1)(n+2)3n3=13