The value of limn→∞ cosx2cosx4cosx8…cosx2n, is
1
sinxx
xsinx
none of these
We know that
cosAcos2Acos4A…cos2n−1A=sin2nA2nsinA
Taking A=x2n, we get
cosx2ncosx2n−1…cosx4cosx2=sinx2nsinx2n∴ limn→∞ cosx2cosx4⋯cosx2n−1cosx2n=limn→∞ sinx2nsinx2n=limn→∞ sinxxx/2nsinx/2n=sinxx