The value of limn→∞ ∑K=1n Kn2+K2
log2
log4
log3
limn→∞∑k=1n Kn2+K2=limn→∞∑k=1n Kn2+K2 =limn→∞∑k=1n 1n2×K1+Kn2 =limn→∞∑k=1n 1n×K/n1+Kn2 =∫01x1+x2dx =12log1+x201 =12log2