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The value of

limn1n+n(n+1)2+n(n+2)2++n(2n1)2 is

 

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detailed solution

Correct option is C

Required  limit −limn→∞ ∑r=0n−1 n(n+r)2=limn→∞ 1n∑r=0n−1 11+rn2=∫01 dx(1+x)2=−11+x01=−12+1=12


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limn1n+1+1n+2++16n is equal to


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