The value of
limn→∞ 1n+n(n+1)2+n(n+2)2+⋯+n(2n−1)2 is
1
1/3
1/2
3/2
Required limit −limn→∞ ∑r=0n−1 n(n+r)2
=limn→∞ 1n∑r=0n−1 11+rn2=∫01 dx(1+x)2=−11+x01=−12+1=12