The value of limx→b x−a−b−ax2−b2, for b>a
14ba−b
14bb−a
14aa−b
1bb−a
We have,
limx→b x−a−b−ax2−b2=limx→b x−b(x−b)(x+b){x−a+b−a}=limx→b 1(x+b){x−a+b−a}=12b{2b−a}=14bb−a