First slide
Introduction to limits
Question

The value of limx0(cosx)cotx, is

Moderate
Solution

We have,

limx0(cosx)cotx=limx0(1+cosx1)cotx=limx012sin2x2cotx=elimx02sin2(x/2)cotx=elimx02sin2(x/2)2sin(x/2)cosx/2=elimx0tan(x/2)cosx=e0=1

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