First slide

Introduction to limits

Question

The value of $lim_{x \to \infty} \frac{\log x}{x^{n}}, n > 0$ , is

Moderate

A

0
B

1
C

$\frac{1}{n}$
D

$\frac{1}{n!}$

Solution

We have,
$lim_{x \to \infty} \frac{\log x}{x^{n}} = lim_{x \to \infty} \frac{1}{n x^{n}} = 0 [By L' Hospital's Rule]$

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