The value of limx→0 sin⁡loge⁡(1+x)log⁡(1+sin⁡x) is equal to

limx→0 sin⁡loge⁡(1+x)log⁡(1+sin⁡x)It is an indeterminate 00 form.=limx→0 cos⁡loge⁡(1+x)⋅1(1+x)⋅(1)1(1+sin⁡x)(0+cos⁡x)=cos⁡loge⁡1⋅(1)1⋅cos⁡0=cos⁡0cos⁡0=11=1