The value of limx→0 1+sinx−cosx+log(1−x)x3 is
1/2
−1/2
0
1
We have,
limx→0 1+sinx−cosx+log(1−x)x3 =limx→0 1+x−x33!+x55!−…−1−x22!+x44!−x66!…+−x−x22−x33−x44x3=limx→0 −13!−13+x215!−15+…=−16−13=−12