The value of limx→∞ π2−tan−1x1/x2, is
0
1
-1
e
Let y=limx→∞ π2−tan−1x1x 00 form
∴ logy=limx→∞ 1xlogπ2−tan−1x⇒ logy=limx→∞ logπ/2−tan−1xx ∞∞ form
⇒ logy=limx→∞ −11+x2π2−tan−1x [Using L'Hospital's Rule]
⇒logy=limx→∞ 2x1+x22−11+x2 [ Using L'Hospital's Rule]
⇒ logy=limx→∞ −2x1+x2=0⇒y=e0=1