First slide
Introduction to limits
Question

The value of limx0tanxsinxx3, is

Moderate
Solution

We have,

limx0tanxsinxx3=limz0sinx(1cosx)x3cosx=limx0sinxx×1cosxx2×1cosx=1×12×11=12

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App