The value of limx→0 tanπ4+x1/x, is
e
e2
2e
1e2
We have,
limx→0 tanπ4+x1x=limx→0 1+tanx1−tanx1/x=limx→0 1+2tanx1−tanx1/x=elimx→0 2tanx1−tanx⋅1x=elimx→0 21−tanx×tanxx =e2