First slide
Evaluation of definite integrals
Question

The value of  limx00xcos t2dtx is 

Moderate
Solution

Let f(x)=0xcos t2dt and g(x)=x. Then f(0)=g(0)=0.

 limx0f(x)g(x)=limx0f(x)g(x) limx00xcos t2dtx=limx0cos x21cos 001=limx0cos x21=cos 0=1.

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