The value of limx→1 (1−x)tanπx2, is
π/2
π+2
2/π
none of these
We have,
limx→1 (1−x)tanπx2=limx→1 (1−x)cotπ2−π2x=2πlimx→1 π2(1−x)tanπ2(1−x)=2π×1=2π