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Q.

The value of limx→0 2x3(tan⁡x−sin⁡x)2x2 is

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a

e2

b

e

c

1e

d

-1

answer is B.

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Detailed Solution

limx→0 1+2x3(tan⁡x−sin⁡x)−12/x2=elimx→02(tan⁡x−sin⁡x)−x3⋅2x5 =elimx→022x−x33+2x515−⋯−x−x33!+x55!⋯−x3x5=elimx→0 22x58+x7 and higher powers of xx5=e1/2=e
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