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Q.

The value of limx→0 ∫−xx f(t)dt∫02x f(t+4)dt is (where f is a continuous function and  f(x) > 0 for all x)

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a

f(0)

b

0

c

f(4)/f(0)

d

f(0)/f(4)

answer is D.

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Detailed Solution

limx→0 ∫−xx f(t)dt∫02x f(t+4)dt00 form =limx→0 (1)f(x)−(f(−x))(−1)2f(2x+4)=limx→0 f(x)+f(−x)2f(2x+4) [∵f is continuous ]=f(0)+f(0)2f(4)=f(0)f(4)
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