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The value of $lim_{x \to 0} \frac{\int_{- x}^{x} f (t) d t}{\int_{0}^{2 x} f (t + 4) d t}$ is (where $f$ is a continuous function and $f (x) > 0$ for all $x$ )

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Correct option is D

limx→0 ∫−xx f(t)dt∫02x f(t+4)dt00 form =limx→0 (1)f(x)−(f(−x))(−1)2f(2x+4)=limx→0 f(x)+f(−x)2f(2x+4) [∵f is continuous ]=f(0)+f(0)2f(4)=f(0)f(4)

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The value of limx→0 ∫−xx f(t)dt∫02x f(t+4)dt is (where f is a continuous function and f(x) > 0 for all x)

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The value of $lim_{x \to 0} \frac{\int_{- x}^{x} f (t) d t}{\int_{0}^{2 x} f (t + 4) d t}$ is (where $f$ is a continuous function and $f (x) > 0$ for all $x$ )