The value of limx→1 7+x23−3+x2x−1 is
−13
32
−14
14
limx→1 7+x23−3+x2x−1
It is an indeterminate 00form
On applying L' Hospital's rule, we get
limx→1 137+x2−23⋅2x−123+x2−12⋅2x1−0=13(8)−23⋅2−22(4)−12=23(2)−2−22(2)−1=2314−12=−13