First slide

Introduction to limits

Question

The value of $lim_{x \to \infty} {(\frac{x - 1}{x + 1})}^{x}$ is

Moderate

A

0
B

$e^{- 1}$
C

$e^{- 2}$
D

$e^{- 3}$

Solution

We have,
$lim_{x \to \infty} {(1 - \frac{2}{x + 1})}^{x} = e^{lim_{x \to \infty} \frac{- 2 x}{x + 1}} = e^{- 2}$

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