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a
13
b
23
c
1
d
43
answer is B.
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Detailed Solution
We know that a−b=a3−b3a2+ab+b2∴ limx→∞ x3+x23−x3−x23=limx→∞ x3+x2−x3−x2x3+x22/3+x3−x21/3x3+x21/3+x3−x22/3=limx→∞ 2x2x3+x22/3+x3−x21/3x3+x21/3+x3−x22/3=limx→∞ 21+1x2/3+1−1x1/31+1x1/3+1−1x2/3=21+1+1=23