First slide
Introduction to limits
Question

The value of  limx0a2ax+x2a2+ax+x2a+xax ,is 

Moderate
Solution

We have,

limx0a2ax+x2a2+ax+x2a+xax=limx02ax(a+x+ax)2xa2ax+x2+a2+ax+x2=limx0a(a+x+ax)a2ax+x2+a2+ax+x2=2a3/22a=a

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