The value of limx→2 x−2+x−2x2−4 is

limx→2 x−2+x−2x2−4At x→2,it is an indeterminate 00 form.On applying Li Hospital's rule, we getlimx→2 12x−2⋅1+12x−012x2−4⋅2x=limx→2 121x−2+1xxx−2x+2=limx→2 12x+x−2xx−2xx−2x+2=limx→2 12x+x−2xxx+2=122222+2=12⋅12⋅2=12