The value of the limit limx→0 11/sin2x+21/sin2x+…+n1/sin2xsin2x is
∞
0
n(n+1)2
n
limx→0 11/sin2x+21/sin2x+…+n1/sin2xsin2x
put 1sin2x=t≥1
∴limt→∞ 1t+2t+…+nt1/t =limt→∞ nt1/t1nt+2nt+…+11/t =nlimt→∞ 1nt+2nt+…+11/t=n[0+0+…+1]0=n