Questions  

The value of the limit limx011/sin2x+21/sin2x++n1/sin2xsin2x is

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a
b
0
c
n(n+1)2
d
n
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detailed solution

Correct option is D

limx→0 11/sin2⁡x+21/sin2⁡x+…+n1/sin2⁡xsin2⁡xput 1sin2⁡x=t≥1∴limt→∞ 1t+2t+…+nt1/t =limt→∞ nt1/t1nt+2nt+…+11/t =nlimt→∞ 1nt+2nt+…+11/t=n[0+0+…+1]0=n


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