First slide
Introduction to limits
Question

The value of the limit limx011/sin2x+21/sin2x++n1/sin2xsin2x is

Moderate
Solution

limx011/sin2x+21/sin2x++n1/sin2xsin2x

put 1sin2x=t1

limt1t+2t++nt1/t =limtnt1/t1nt+2nt++11/t =nlimt1nt+2nt++11/t=n[0+0++1]0=n

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