The value of 0·2log514+18+116+⋯ is
4
log 4
log 2
none of these
We have,14+18+116+⋯=1/41−1/2=12Hence,0.2log5 14+18+116+⋯=0.2log5 12 =15log512 =5−12log512 =(5)−2log512 =(5)log54 =4